Where is admin?

I'ts important.

Thank.

## Where is Administration forum.opencaching.us ??

- TermiteHunter
- Site Admin
**Posts:**1145**Joined:**Sun Aug 29, 2010 7:12 pm

### Re: Where is Administration forum.opencaching.us ??

Congrats.

You are currently the 11th post with the same title of those that remain only because the OP has not posted any other spam yet.

You also have the second most popular post under that title.

I do not think any of those posts remain after the OP posted spam.

You have used the term "Thank" incorrectly as nearly all before you do.

Now take the 11 (11th post) and add the 2 (2nd most popular) and you have 13

9.5% use "Regards" in their posts, 89.5% use "Thank", 1% use something else or nothing.

Take the 9 subtract the first digit 8 in the next number for 1. Now add the .5 to the .5 for 1 and the last digit is 1. the remaining digit is 9 (from 89.5)

1+1+1+9 = 12

13 is greater than 12 by 1

Add 1 to 12 and you have 13

Subtract 1 from 13 for 13

Subtract 12 from 13 to get 1

Add those together to get 28

Subtract 13 from 28 for 15

Subtract the number of ones for 15 -2 =13

Still have a remaining 13 so 13, 13.

I have typed "1" 28 times to this point. 28 minus 13 = 15.

I have typed "15" 3 times 15 minus 3 =12

I need one more 1 (so there it is) 12 plus my new 1 =13

Coincidence? I think not.

You are currently the 11th post with the same title of those that remain only because the OP has not posted any other spam yet.

You also have the second most popular post under that title.

I do not think any of those posts remain after the OP posted spam.

You have used the term "Thank" incorrectly as nearly all before you do.

Now take the 11 (11th post) and add the 2 (2nd most popular) and you have 13

9.5% use "Regards" in their posts, 89.5% use "Thank", 1% use something else or nothing.

Take the 9 subtract the first digit 8 in the next number for 1. Now add the .5 to the .5 for 1 and the last digit is 1. the remaining digit is 9 (from 89.5)

1+1+1+9 = 12

13 is greater than 12 by 1

Add 1 to 12 and you have 13

Subtract 1 from 13 for 13

Subtract 12 from 13 to get 1

Add those together to get 28

Subtract 13 from 28 for 15

Subtract the number of ones for 15 -2 =13

Still have a remaining 13 so 13, 13.

I have typed "1" 28 times to this point. 28 minus 13 = 15.

I have typed "15" 3 times 15 minus 3 =12

I need one more 1 (so there it is) 12 plus my new 1 =13

Coincidence? I think not.

- TermiteHunter
- Site Admin
**Posts:**1145**Joined:**Sun Aug 29, 2010 7:12 pm

### Re: Where is Administration forum.opencaching.us ??

From above

"subtract 1 from 13 for 13"

Should have been 12. Typing error.

The formula is correct.

"subtract 1 from 13 for 13"

Should have been 12. Typing error.

The formula is correct.